(x+2)/(x-1)*(4x-4)/(x^2-4)

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Solution for (x+2)/(x-1)*(4x-4)/(x^2-4) equation: 


D( x )

x^2-4 = 0

x-1 = 0

x^2-4 = 0

x^2-4 = 0

1*x^2 = 4 // : 1

x^2 = 4

x^2 = 4 // ^ 1/2

abs(x) = 2

x = 2 or x = -2

x-1 = 0

x-1 = 0

x-1 = 0 // + 1

x = 1

x in (-oo:-2) U (-2:1) U (1:2) U (2:+oo)

(((x+2)/(x-1))*(4*x-4))/(x^2-4) = 0

((x+2)*(4*x-4))/((x-1)*(x^2-4)) = 0

( 4*x-4 )

4*x-4 = 0 // + 4

4*x = 4 // : 4

x = 4/4

x = 1

( x+2 )

x+2 = 0 // - 2

x = -2

x in { 1} 

x in { -2} 

x belongs to the empty set

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